设图G是有5个结点的连通图,结点度数总和为10,则可从G中删去6条边后使之变成树.( )
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设图G是有5个结点的连通图,结点度数总和为10,则可从G中删去6条边后使之变成树.( )
无向图G的结点数比边数多1,则G是树.( )
设G是一个连通平面图,且有6个结点11条边,则G有7个面.( )
结点数v与边数e满足e=v的无向连通图就是树.( )
已知图G中有1个1度结点,2个2度结点,3个3度结点,4个4度结点,则G的边数是15.( )
正确
错误
设图G是有6个结点的连通图,结点的总度数为18,则可从G中删去4条边后使之变成树.( )
若图G=<V, E>中具有一条汉密尔顿回路,则对于结点集V的每个非空子集S,在G中删除S中的所有结点得到的连通分支数为W,则S中结点数|S|与W满足的关系式为W|S|.( )
设G是一个有7个结点16条边的连通图,则G为平面图.( )
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